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The Ease of Wolfram|Alpha, the Power of Mathematica: Introducing Wolfram|Alpha Notebook Edition—Stephen Wolfram Writings
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real analysis - How can I prove the Wolfram Alpha result $\int_0^{\infty} \frac{(\sin x)^2}{x^2-\pi ^2} dx=-\frac1{2\pi}$? - Mathematics Stack Exchange
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